Problem 57 (with incorrect version (due to limitatations of size of long double) in C).

57.c

@@ -0,0 +1,18 @@
+#include <stdio.h>
+#include <stdlib.h>
+#include <math.h>
+
+int main () {
+    long double numerator = 3;
+    long double denominator = 2;
+    int count = 0;
+    for (int i = 0; i < 1000; i++) {
+        long double newDen = numerator + denominator;
+        long double newNum = newDen + denominator;
+        numerator = newNum;
+        denominator = newDen;
+        if ((int) floor (log10 (numerator)) > (int) floor (log10 (denominator)))
+            count++;
+    }
+    printf ("count: %d\n", count);
+}

57.py

@@ -0,0 +1,11 @@
+numerator = 3
+denominator = 2
+count = 0
+for i in range(0, 1001):
+    newDen = numerator + denominator
+    newNum = newDen + denominator
+    numerator = newNum
+    denominator = newDen
+    if len(str(numerator)) > len(str(denominator)):
+        count += 1
+print count