22 lines
395 B
Python
22 lines
395 B
Python
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import math
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def ithTriangularNum(i):
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return 0.5*i*(i+1)
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def numOfFactors(n):
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s = int(math.sqrt(n))
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factors = 0
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for j in range(1, s):
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if n % j == 0:
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factors += 1
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return factors*2
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factors = 0
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i = 1
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n = ithTriangularNum(i)
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while factors <= 500:
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i += 1
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n = ithTriangularNum(i)
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factors = numOfFactors(n)
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print i, n, factors
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